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  • Find the coordinates of the point where the line through (– 1, 1, – 8) and (5, – 2, 10) crosses the ZX-plane.  

Find the coordinates of the point where the line through (– 1, 1, – 8) and (5, – 2, 10) crosses the ZX-plane.

 

Answers (1)

\\$Equation of line passing through (-1,1,-8) and (5,-2,10) $ \\ \frac{x+1}{5+1} = \frac{y-1}{-2-1}=\frac{z+8}{10+8} = \lambda

x =6 \lambda-1, y= -3 \lambda+1, z=18 \lambda-8

\\$Equation cut ZX plane $ \\\rightarrow $y-coordinate $=0

\\ -3 \lambda+1 = 0 \\\\ \lambda = \frac{1}{3}

$ The point of intersection is (1,0,-2)

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Safeer PP

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