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  • Find the curved surface area of the frustum of a cone , the diameters of whose circular ends are 20 m and 6 m and its height is 24 m .     &nb

Find the curved surface area of the frustum of a cone , the diameters of whose circular ends are 20 m and 6 m and its height is 24 m .

 

 
 
 
 
 

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$Given Diameter (D_1)= 20 m , D_2 = 6 m $\\ \mathrm{R}=10 \mathrm{m} , r =3 \mathrm{m}, \mathrm{h}=24 \mathrm{m} \\ l= \sqrt{(h)^{2}+(R-r)^{2}}\\ l=\sqrt{(24)^{2}+(10-3)^{2}}=25 \mathrm{m} \\ \mathrm{ $Curved Surface Area $ }=\pi(R+r) \times l \\ =\pi(10+3) 25\\ =325 \pi \ \ \mathrm{m}^{2}

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