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Find the electric field intensity due to a uniformly charged spherical shell at a point (i) outside the shell and (ii) inside the shell. Plot the graph of electric field with distance from the centre of the shell. 

 

 

 

 
 
 
 
 

Answers (1)

(i) Outside shell

Consider a point P outside the shell at a distance r. Consider a spherical Gaussian surface of radius r.

Then  by Gauss law :

Flux enclosed by the surface

\phi =\oint E.ds=\frac{q}{\varepsilon _{o}}

E\times 4\pi r^{2}=\frac{q}{\varepsilon _{o}}

E = \frac{q}{4\pi \varepsilon _{o}r^{2}}

(ii) Since inside a sperical shell charge =0,

therefore electric field E= 0

Posted by

Safeer PP

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