Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Find the value of p for which the following lines are perpendicular: <img alt="\frac{1-x}{3}=\frac{2y-14}{2p}=\frac{z-3}{2};\: \frac{1-x}{3p}=\frac{y-5}{1}=\frac{6-z}{5}" src="https://entrancecorner.codecogs.com/gif.latex?%5Cfrac%7B1-x%7D%7B3

Find the value of p for which the following lines are perpendicular:

\frac{1-x}{3}=\frac{2y-14}{2p}=\frac{z-3}{2};\: \frac{1-x}{3p}=\frac{y-5}{1}=\frac{6-z}{5}

 

 

 

 

 
 
 
 
 

Answers (1)

\frac{1-x}{3}=\frac{2y-14}{2p}=\frac{z-3}{2}

\frac{1-x}{3p}=\frac{y-5}{1}=\frac{6-z}{5}

\frac{x-1}{-3}=\frac{y-7}{p}=\frac{z-3}{2}........(1)

\frac{x-1}{-3p}=\frac{y-5}{1}=\frac{z-6}{-5}........(2)

D.R of (1) (-3,p,2)   D.R of (2) (-3p,1,-5)

DR_1.DR_2\Rightarrow (-3)(-3p)+(p)(1)+2(-5)=0

\Rightarrow 9p+p-10=0

\Rightarrow 10p=10

\Rightarrow p=1

Posted by

Ravindra Pindel

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

Iran-Israel War: CBSE cancels Class 12 board exams in 7 Middle East countries; result formula to be announced
anam-khan

CBSE 2026 Paper LIVE: Class 12 Hindi exam over; question paper analysis, answer key soon
anam-khan

CBSE Class 12 English Paper Analysis: Questions easy, ‘student-friendly’; can 'score above 90%'

Latest Question