find the value of x^3-8y^3-36xy-216 ,when x=2y+6 .

Answers (1)

solution: we have ,

x^3-8y^3-36xy-216

=x^3+(-2y)^3+(-6)^3-39(x)(-2y)(-6) 

=(x-2y-6)(x^2+4y^2+36+2xy-12y+6x)

=[x=2y+6Rightarrow x-2y-6=0]

Rightarrow  0	imes (x^2+4y^2+36+2xy-12y+6x)=0

 

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