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find the zeroes of2x3-11x2+17x-6=0

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2x³ - 11x² + 17x - 6 = 0
for x = 2 ; value of the equation is zero
(x - 2)(2x² - 7x + 3) = 0
(x - 2)(2x² - 6x - x +3) = 0
(x - 2){2x(x - 3) -1(x - 3)} = 0
(x - 2)(2x - 1)(x - 3) = 0
x = 2,1/2,3

Posted by

shubham.krishnan

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