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  • For the following frequency distribution, draw a cumulative frequency curve (ogive) more than type and hence obtain the median value

For the following frequency distribution, draw a cumulative frequency curve (ogive) of ‘more than type’ and hence obtain the median value.

Class: 0-10 10-20 20-30 30-40 40-50 50-60 60-70
Frequency: 5 15 20 23 17 11 9
 

 

 
 
 
 
 

Answers (1)

Class 0-1 10-20 20-30 30-40 40-50 50-60 60-70
freq. 5 15 20 23 17 11 9
c.f. more than type 100 100-5=95 95-15=80 80-20=60 60-23=37 37-17=20 20-11=9

N=\sum F=5+15+20+23+17+11+9

        \Rightarrow N=\sum f=100

Now calculate c.f of more than type taking account into lower limits.

After that plot the graph of freq. vs c.f

Now find \frac{N}{2}=\frac{100}{2}

                \Rightarrow 50

Now draw a line perpendicular to y-axis from '50' \rightarrow line\; AB

\rightarrow From the point, B draw a line which cuts x-axis and is perpendicular to x- axis

\rightarrow The point where the line cuts x-axis is the median

\rightarrow Median =37

Posted by

Safeer PP

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