From a right circular cylinder with height 10 cm and radius of base 6 cm , a right circular cone of the same height and base is removed . Find the volume of the remaining solid.

Answers (1)

Solution : Let V_1 and V_2 be the volumes of the right circular cylinder and cone respectively . 

                Then , 

                          V_1=frac227	imes6 	imes6	imes 10cm^3                                 [Using : V_1=pi r^2h]

            and ,     V_2=frac13	imes frac227	imes6 	imes6 	imes10 cm^3                           [Using :V_2=frac13pi r^2h]

	herefore           Volume of the remaining solid =V_1-V_2

Rightarrow          Volume of the remaining solid =(frac227	imes6	imes 6 	imes 10- frac13	imes frac227	imes 6 	imes 6 	imes 10)cm^3

Rightarrow           Volume of the remaining solid =754.28cm^3

 

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