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From a right circular cylinder with height 10 cm and radius of base 6 cm , a right circular cone of the same height and base is removed . Find the volume of the remaining solid.

Answers (1)

D Deependra Verma

Solution : Let $V_1$ and $V_2$ be the volumes of the right circular cylinder and cone respectively .

Then ,

$V_1=frac227 imes6 imes6 imes 10cm^3$ $[Using : V_1=pi r^2h]$

and , $V_2=frac13 imes frac227 imes6 imes6 imes10 cm^3$ $[Using :V_2=frac13pi r^2h]$

$herefore$ Volume of the remaining solid $=V_1-V_2$

$Rightarrow$ Volume of the remaining solid $=(frac227 imes6 imes 6 imes 10- frac13 imes frac227 imes 6 imes 6 imes 10)cm^3$

$Rightarrow$ Volume of the remaining solid $=754.28$ $cm^3$

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