How can I get sum of 1,3,5,7,9,11,13,15 upto 30 terms

Answers (1)

1+3+5.... 30 terms

Sn= n{2a+(n-1)d}/2

Here a=1, n=30, d=2

Sn= 30{2+(30-1)2}/2

Sn = 900

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