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how do i solve this

Answers (1)

VA and VB are given as 10 and 20 m/s respectively

Also, it is found that t=2.2 sec

In the first step, we have

\\(30-V_At)^2+(40-V_Bt)^2=s^2\\s^2=(30-10\times2.2)^2+(40-20\times2.2)^2\\s^2=(30-22)^2+(40-44)^2\\s^2=8^2+(-4)^2\\s^2=64+16\\s^2=80\\s=\sqrt{80}\\s=\sqrt{16\times5}=4\sqrt{5}m

Posted by

Safeer PP

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