How many 176Omega resistors (in parallel) are required to carry 5 A on a 220 V line?

Answers (1)

Given : V=220V and I =5A

R=fracVI=frac2205=44Omega

Let x number of resistors are connected in parallel to obtain 44 Ohm equivalent resistance.

Thus,

         frac1R=frac1176+frac1176+.......................to, , x, , times

Rightarrow frac144=fracx176

Rightarrow x=frac17644=4

Hence, 4 resistors  of 176 Ohm are connected in parallel to obtain 44 Ohm

 

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