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How many different ways can you arrange the letters in the word "PERMUTE"?

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$\text { Number of arrangements }=\frac{n!}{k_{1}!\times k_{2}!\times \cdots \times k_{r}!}$

$\begin{gathered} \text { Number of arrangements }=\frac{7!}{2!} \\ 7!=7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1=5040 \\ 2!=2 \times 1=2 \\ \text { Number of arrangements }=\frac{5040}{2}=2520 \end{gathered}$

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Divya Sharma

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