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IF 14464 = 124; 19627 = 143; 12108 = 112 THAN 225125 = ??

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$eginarrayl extIn 14464, 19627,12108 extfirst three digits are square of any number and remaining are cube\ 14464=(12)^2(4)^3=124\ \ 19627=(14)^2(3)^3=143\ \ 12108=(11)^2(2)^3=112\ \ extsimilarly,\ \ 225125=(15)^2(5)^3=155endarray$

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Deependra Verma

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