# If 2x+3y=13 and xy=6 , find the value of 8x^3+27y^3

Solution: We have ,

$\\ 2x+3y=13\\ \\(2x+3y)^3=8x^3+27y^3+3\times 2x\times 3y(2x+3y)=13^3\\ \\\Rightarrow 8x^3+27y^3+18\times 6\times 13=2197\\ \\\Rightarrow 8x^3+27y^3=2197-1404\\ \\\Rightarrow 8x^3+27y^3=793$

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