if a+b+c=0 ,then prove that a^3+b^3+c^3=3abc

Answers (1)

solution:   proof  we know that ,

                 a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)

                 putting a+b+c=0  on R.H.S  , we get

                     a^3+b^3+c^3-3abc=0

                 Rightarrow a^3+b^3+c^3=3abc

            

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