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If a boy walks from his home to the school at 4km/hr he reaches the school 10mins earlier than d scheduled time. however if he walks at 3 km/hr, he reaches 10 mins late. the distance from the school to the house is :

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\\ Let \ the \ distance \ of \ a \ school \ be \ x \ km$, then \\ \\ $\Rightarrow \frac{x}{3}-\frac{x}{4}=\frac{20}{60}$ $\Rightarrow \frac{x}{12}=\frac{1}{3} \Rightarrow x=\frac{12}{3}=4 km$

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Deependra Verma

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