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if a maganet is suspended at angle 30 to the magnetic meridian the dip needle makes angle of 45 with the horizontal the real dip is

 

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\begin{gathered} \tan 45^{\circ}=\tan \delta \cdot \cos 30^{\circ} \\ 1=\tan \delta \cdot \frac{\sqrt{3}}{2} \\ \tan \delta=\frac{1}{\frac{\sqrt{3}}{2}}=\frac{2}{\sqrt{3}} \\ \delta=\tan ^{-1}\left(\frac{2}{\sqrt{3}}\right) \approx \tan ^{-1}(1.1547) \approx 49.1^{\circ} \end{gathered}

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