If a man's face is 25cm in front of a shaving mirror producing an erect image 1.4 times the size of the face, then find the focal length of the mirror used.
Given- $u = -25\ \text{cm},\ m = +1.4$
Magnification $m = \frac{v}{u} \Rightarrow v = -35\ \text{cm}$
$\frac{1}{f} = \frac{1}{v} + \frac{1}{u} = -\left( \frac{1}{35} + \frac{1}{25} \right) = -\frac{60}{875} = -\frac{12}{175}$
$f = -\frac{175}{12} \approx -14.6\ \text{cm}$
Therefore, the focal length of the mirror is approximately 14.6 cm (The negative sign indicates it is a concave mirror).