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If a positive number exceeds its positive square roots by 12,then find the number.

Answers (1)

Assume x2 is positive number. 

ATQ

x^2 = x + 12\\ x^2- x - 12=0\\ x^2- 4x +3x - 12=0\\ x(x-4) +3 (x-4)=0\\ (x-4)(x+3)=0\\ x = - 3($ Not possible as x is positive number $) \\ x = 4\\

Hence the required number is 16.

Posted by

Ravindra Pindel

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