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If (a/x)>0 , (b/x) >0 , (ab/x^2)<1 and tan^-1(a/x)+tan^-1(b/x)=pi/2 , then x equals

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Solution:

$an^-1[fracfracax+fracbx1-fracabx^2]=fracpi2$

$Rightarrow$ $1-fracabx^2=0$

$Rightarrow$ $x=sqrtab.$

Posted by

Deependra Verma

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