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If a:b=c:d=e:f=1:2,then(3a+5c+7e):(3b+5d+7f) is

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Given, $fracab = fraccd =fracef = frac12$

$Rightarrow a = frac12 b, c= frac12d, e = frac12f$

Now, $$$frac3a+5c+7e3b+5d+7f = frac3 imes frac12b +5 imes frac12d + 7 imes frac12f 3b + 5d + 7f$

$$$Rightarrow frac12[frac3b +5d+7f3b +5d +7f]$

$Rightarrow frac12$

Hence, Answers = $frac12$

Posted by

Deependra Verma

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