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If cos theta = 0.6 show that 5 sin theta - 3 tan theta =0

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$$Given $ :\cos \theta = 0.6 = \frac{3}{5} \\\\ \cos \theta = \frac{\sin \theta }{\tan \theta } = \frac{3}{5} \\\\ 5 \sin \theta = 3\tan \theta \\ 5 \sin \theta -3\tan \theta =0 \\ $ Hence proved$

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Ravindra Pindel

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