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If cos theta= âˆš3Ã·2 then find the value of 4cos^3 theta-3 cos thetaâ€‹

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$\cos \theta = \frac{\sqrt{3}}{2} \\ \theta = \frac{\pi}{6}\\ Now \\ 4 \cos^3 \theta - 3 \cos \theta = 4 (\frac{\sqrt{3}}{2})^3 - 3 (\frac{\sqrt{3}}{2})\\ = \frac{3\sqrt{3}}{2} -\frac{3\sqrt{3}}{2}=0$

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Ravindra Pindel

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