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If f(x)=x/2 , g(x)=x^2 and h(x)=2x, then the value of (fogoh)(3) is

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Solution: We have , $f(x)=fracx2$ , $g(x)=x^2$ and $h(x)=2x$

$Rightarrow$ $(fogoh)(3)=f[g(h(3))]=f[g(6)]=f(36)=18.$

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Deependra Verma

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