If ln x/(b-c)=ln y/(c-a)=ln z/(a-b), then the value of x^(b+c) . y(c+a) . z^(a+b) , is

Answers (1)

Solution:     Let     ,

                    fracln x(b-c)=fracln y(c-a)=fracln z(a-b)=k,

                 \Rightarrow       x=e^k(b-c),y=e^k(c-a)  and  z=e^k(a-b).

                Rightarrow     x^b+ccdot y^c+acdot z^a+b=e^k(b^2-c^2)+k(c^2-a^2)+k(a^2-b^2)=e^0=1

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