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If origin is the centre of a circle with radius 7 units, find the coordinates of any four points on the circle which are not on the axes. (Use the Pythagorean triplets)

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The co-ordinates can be represented as (7cos(Ф),7sin(Ф))
where Ð¤ ∈ [0,2π]
So we can take any four points Ф=30,45,60 and 120
The co-ordinates of four points on circle are (7√3/2,7/2), (7/√2,7/√2), (7/2,7√3/2) and (-7/2,7√3/2)

 

Posted by

Ravindra Pindel

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