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if sec A - tan A = 1/3 then find sec A + tan A

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$\sec A - \tan A =\frac{1}{3} \\ $ we know $ \ \ \sec^2 A -\tan^2 A = 1 \\ (\sec A - \tan A)(\sec A + \tan A) = 1 \\ sec A + tan A = \frac{1}{\sec A - \tan A} =3$

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Ravindra Pindel

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