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If sec A - tan A = 2 then find the value of sec A + tan A

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$\sec^2 A = 1 + \tan ^2 A \\ \sec^2 A - \tan ^2 A =1 \\ (\sec A + \tan A)(\sec A - \tan A) = 1 \\ \sec A + \tan A = \frac{1}{\sec A - \tan A} \\\\ \sec A + \tan A = \frac{1}{2} \because \sec A - \tan A = 2 \\ \\$

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Ravindra Pindel

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