If Sin θ = 3/5, find cos θ
Given- $\sin \theta = \frac{3}{5}$
To find - cos θ
Solution- Since $\theta$ is acute, we use the identity:
$\cos \theta = \sqrt{1 - \sin^2 \theta} = \sqrt{1 - \left( \frac{3}{5} \right)^2} = \sqrt{1 - \frac{9}{25}} = \sqrt{\frac{16}{25}} = \frac{4}{5}$