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Get Answers to all your Questions
If sin A + Cos A = a and sin³A + cos³A = b ,then find the value of 3a – 2b
Answers (1)
3a - 2b = 3 sin A + 3 Cos A - 2 Sin³ A - 2 Cos³ A
= sin A + Cos A + 2 Sin A (1 - Sin² A) + 2 Cos A (1 - Cos ² A)
= sin A + Cos A + 2 sin A cos² A + 2 cos A Sin² A
= (sin A + Cos A) + 2 sin A cos A ( sin A + Cos A)
= (sin A + Cos A) (1 + sin 2 A)
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