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if sin theta = 3/5 than find sin^2 theta + cos^2 theta

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\sin \theta = \frac{3}{5} \\\\ \cos \theta = \frac{\sqrt{5^2-3^2}}{5} \\\\ \cos \theta = \frac{4}{5} \\\\ \sin^2 \theta + \cos^2 \theta = (\frac{3}{5})^2 + (\frac{4}{5})^2 \\ = \frac{9 + 16 }{25} \\ =1 \\\\ \sin^2 \theta + \cos^2 \theta =1 $ is always true for any value of $ \theta

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Ravindra Pindel

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