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If the area of a triangle ABC is a^2 -(b-c)^2 , then tan( A/2 ) equals

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Solution: $sqrts(s-a)(s-b)(s-c)=a^2-(b-c)^2$

$sqrts(s-a)(s-b)(s-c)= (a+b-c)(a-b+c)$

$sqrts(s-a)(s-b)(s-c)= (2s-2c)(2s-2b)=4(s-c)(s-b).$

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Deependra Verma

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