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  • If the HCF of 210 and 55 is expressible in the form 210*5+55y, find y.

If the HCF of 210 and 55 is expressible in the form 210*5+55y, find y.

Answers (1)

210 = 2x3x5x7

55=5x11

 HCF(210,55) = 5

ATQ

210x5+55y=5

55y = -1045

y =-1045/55 = -19 

Posted by

Ravindra Pindel

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