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If the ratio of de Broglie wavelengths of electron waves in two orbits is 3:5. What will be the ratio of kinetic energy ?

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KE is inversely proportional to λ2, 

Therefore, the ratio of kinetic energies of electron will be:

KE1: KE2 =  λ22 : λ12 = 52 : 32 = 25 : 9

Posted by

Sumit Saini

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