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  • If the sum of the square of three positive number is 14 and the sum of their product taking two at a time is 11 find the sum of the number​

If the sum of the square of three positive number is 14 and the sum of their product taking two at a time is 11 find the sum of the number​

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$ Assume a,b,c are three positive numbers $ \\ $ Given : $ a^2 + b^2 + c^2 =14 \\ ab + bc +ac = 11 \\ (a+b+c)^2 = a^2 + b^2 + c^2 + 2(ab + bc +ac ) \\ = 14 + 2(11)\\ =36 \Rightarrow (a+b+c) =6\\

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Ravindra Pindel

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