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  • If the tangent to the curve y=x+siny at a point (a,b) is parallel to the line joining (0,3/2) and (1/2,2) then

If the tangent to the curve y=x+siny at a point (a,b) is parallel to the line joining (0,3/2) and (1/2,2) then

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Solution: 

\ (dy/dx);at (a,b)=(2-3/2)/(1/2-0)\ \Rightarrow (1+cosb)=1\ \Rightarrow cosb=0

point P(a,b) lies on curve

\ b=a+sinb\ \Rightarrow b=apm 1\ \Rightarrow b-a=pm 1

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Deependra Verma

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