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If three vectors are a(1 ,1,1) ,b (4,-2,3), c(1,-2,1) then find the vector of magnitude 6 unit which is parallel to the vector 2a-b+3c.

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eginarrayl	extGiven that,\ veca=left(1,1,1
ight), vecb=left(4,-2,3
ight) & vecc=left(1,-2,1
ight)\ vecr=2veca-vecb+3vecc \ vecr=2left(i+j+k
ight)-left(4i-2j+3k
ight)+3left(i-2j+k
ight)=i+2k\ 	extUnit vector is left(vecr
ight)=fraci+2ksqrt5\ 	extLet vecA, 	extis parallel to vecr 	extand magnitude is 6.\ vecA=6left(fraci+2ksqrt5
ight)endarray

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Deependra Verma

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