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If x^2+2ax+10-3a>0 for all x then

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Solution: We have , $x^2+2ax+10-3a>0$

$ax^2+bx+c> 0,forall x$ if $a> 0$ , $D< 0$

Here $4a^2-4(10-3a)< 0Rightarrow a^2+3a-10< 0$

$Rightarrow$ $(a+5)(a-2)< 0Rightarrow ain (-5,2).$

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Deependra Verma

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