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  • In a GP the 3rd term is 24 and 6 th term is 192. Find the 10' term

In a GP the 3rd term is 24 and 6 th term is 192. Find the 10'" term .?,??????​

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$ Assume a , ar, $ ar^2 $ ... are in GP.\\ T(3) = ar^2 = 24 ...(i)\\ T(6) =ar^{5} = 192...(ii)\\ Equation (ii)/Equation (i) \\ {r^{5}}/r^{2} = 192/24 =8 \\ r^{3} = 8 =2^3\\ r = 2\\ a =6 \\ T(10) = ar^9 = 6 \times 2^9 = 3072

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Ravindra Pindel

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