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In a single throw of two dice, find the probability of getting a sum of 11

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I'm assuming we're using standard fair 6-sided dice.

There are a total of 6×6=36 possible rolls.

There are two ways to roll an 11: (5,6),(6,5)

And so the odds of rolling an 11 are:

\frac{2}{36}=\frac{1}{18}

Posted by

Deependra Verma

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