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  • In a triangle ABC, if a=6,b=3 and cos(A-B)=4/5, the area of triangles is

In a triangle ABC, if a=6,b=3 and cos(A-B)=4/5, the area of triangles is

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Solution:   

                cos (A-B)=frac45      Rightarrow      an(fracA-B2)=frac13

              fraca-ba+b= an (fracA-B2) anfracC2Rightarrow C=90^circ

    Rightarrow              Delta =9 sq.unit

Posted by

Deependra Verma

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