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In a triangle PQR , Angle R = pi/2 If tan (P/2) and tan (Q/2) are the roots of the equation ax^2+bx+c=0 then

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Solution:  Given ,

                	an fracP2+	an fracQ2=-fracba     and    	an fracP2	an fracQ2=fracca

         Rightarrow      	an (fracP+Q2)= frac-fracba1-fracca  

      As    P+Q=fracpi2Rightarrow 1=frac-ba-cRightarrow c=a+b.

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Deependra Verma

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