In an electrical circuit two resistors of 2 ? and 4 ? respectively are connected in series to a 6 V battery. The heat dissipated by the 4 ? resistor in 5 s will be

Answers (1)

Given resistors are 4Omega ,2Omega are connected in series

Equivalent Resistance = 4Omega +2Omega =6Omega

Voltage = 6V

Current in the resistor = V/R = 6/6 = 1 A

Heat dissipated in resistor = I2Rt=12×4×5=20J

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