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  • In Figure 4, a square OABC is inscribed in a quadrant OPBQ. If OA = 15 cm, find the area of the shaded region. (Use = 3·14)      &nbsp

In Figure 4, a square OABC is inscribed in a quadrant OPBQ. If OA = 15 cm, find the area of the shaded region. (Use \pi = 3·14)

        

 

 

 
 
 
 
 

Answers (1)

OB = \sqrt{15^2 + 15^2} = 15\sqrt2 cm

OB = \text{radius of circle / quadrant} = 15\sqrt2 cm

\begin{align*}\text{Shaded area}& = \text{Area of quadrant - Area of square} \\ & = \frac{1}{4}(3.14)(15\sqrt2)^2 - (15)^2 \\ & = 128.25 \text{ cm}^2 \end{align*}

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Safeer PP

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