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In the given circuit, find :
(a) Total resistance of the network of resistors
(b) Current through ammeter A
(c) Potential difference across $3\; \Omega$ and $4\; \Omega$ resistors

Answers (1)

Total Resistance = ?

$R_{1}=4+2=6$

$R_{2}=3+3=6$

$\frac{1}{R}=\frac{1}{R_{1}}+\frac{1}{R_{2}}$

$\frac{1}{R}=\frac{1}{6}+\frac{1}{6}$

$R=3\; \Omega$

(b) $I=\frac{V}{R}=\frac{6}{3}=2A$

(c) $I_{1}=\frac{V}{R_{1}}=\frac{6}{6}=1A$

$I_{2}=\frac{V}{R_{2}}=\frac{6}{6}=1A$

So, P.D across $3\Omega \Rightarrow V_{3}=I_{2}R_{3}$

$V_{3}=1\times 3$

$V_{3}=3V$

and P.D across $4\Omega \Rightarrow V_{4}=I_{1}R_{4}$

$V_{4}=1\times 4$

$V_{4}=4V$

Posted by

Sumit Saini

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