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Integrate: 1/(1+e^x)

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Solution: We have ,   

               I=intfrac1e^x+1dx

        Multiply Num , and denom . by e^-x

            I=int frace^-x1+e^-xdx      ,   Put e^-x+1=tRightarrow e^-xdx=dt

    Rightarrow   I=-int frac1tdt=-lnleft | t ight |+c=-lnleft | e^-x+1 ight |+c

Posted by

Deependra Verma

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