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Let R denote the set of all real numbers and f:R-->R be a function defined by f(x)=x^2. if A = x belong to R :x<0 then f^-1 (A) equals

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Solution: $f^-1(A)=xin R^+:f(x )in A,$

$f^-1(A)=x in R:f(x)< 0 .=x in R:x^2< 0=Phi .$

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Deependra Verma

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