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  • Let Tr be the rth term of AP, for r=1,2,3 ...... If for some positive integers m and n We have Tm=1/n and Tn=1/m , then Tmn equals

Let Tr be the rth term of AP, for r=1,2,3 ...... If for some positive integers m and n We have Tm=1/n and Tn=1/m , then Tmn equals

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best_answer

Solution: Let a be the first term and d be the common

diffrence of the given AP .Then

\ Tm-Tn=(1/n-1/m)\ \Rightarrow (m-n)d=(m-n/mn)\ \Rightarrow d=1/mn\ \Rightarrow Tmn-Tn=(mn-m)1/mn=1-1/nRightarrow Tmn=1

Posted by

Deependra Verma

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