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On dividing a polynomial $p(x)$ by $x^{2}-4$ , quotient and remainder are found to be $x$ and $3$ respectively. The polynomial $p(x)$ is
Option: 1 $3x^{2}+x-12$
Option: 2 $x^{3}-4x+3$
Option: 3 $x^{2}+3x-4$
Option: 4 $x^{3}-4x-3$

Answers (1)

$\\p(x) = x(x^2-4 ) + 3 \\ p(x) = x^3-4x + 3 \\$

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Safeer PP

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