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P=(3^2000)+(3^-2000) and q=(3^2000)-(3^-2000) than value p^2-q^2 equalto=

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$p=(3^{2000})+(3^{-2000}), \ q=(3^{2000})-(3^{-2000})\\ p^2-q^2=(p+q)(p-q)\\ =((3^{2000})+(3^{-2000})+(3^{2000})-(3^{-2000}))((3^{2000})+(3^{-2000})-(3^{2000})+(3^{-2000}))\\ =2\cdot 3^{2000} \cdot 2 \cdot 3^{-2000}\\ =4$

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Ravindra Pindel

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